# The (ASA) condition for hyperbolic triangles

Basic stategy
Suppose that ABC and PQR are h-triangles.
Then there is a hyperbolic transformation t which maps
A to P,
B to B' on the h-line PQ, on the same side of P as Q, and
C to C' on the same side of the h-line as R.

Note that, as t preserves angle and hyperbolic distance,
d(A,B) = d(P,B'), d(A,C) = d(P,C'), d(B,C) = d(B',C'), and
<ABC = <PB'C', <BAC = <B'PC', <ACB = <PC'B'.

(ASA) condition
If h-triangles ABC and PQR have
 (1)
then the h-triangles are h-congruent.

Proof
Let t be the transformation implied by the Basic Strategy.
Then B' lies on the h-line PQ.
By the Basic Strategy, d(A,B) = d(P,B').
By (2), d(A,B) = d(P,Q), so d(P,B') = d(P,Q), and hence B' = Q.
By the Basic Strategy, <BAC = <QPC'.
By (1), <BAC = <QPR, so C' lies on PR.
By the Basic Strategy, <ABC = <PQC'.
By (3), <ABC = <PQR, so C' lies on QR.
Thus C' lies on PR and on QR.
But the h-lines PR and QR meet only at R, so C' = R.
Thus t maps ABC to PQR, so the h-triangles are h-congruent.