an algebraic characterization of interior and exterior

We know that a projective conic C has equation f(x) = xTMx = 0, with M symmetric.
If P =[p] is not on C, then f(p) will be non-zero, and thus either positive or negative.
It turns out that all p-points inside C have f(p) with the same sign, and all p-points
outside C have f(p) of the opposite sign to that for the interior p-points.

the algebraic interior-exterior theorem
Suppose that C is the projective conic f(x) = xTMx = 0.
Then P = [p] and Q = [q] both lie on the same side of C
if and only if f(p) and f(q) have the same sign.

proof

Note that we can replace M by -M in the equation. This allows us to choose
the equation of C so that the interior corresponds to p-points with f(p) > 0.

We know that the cross-ratio of four collinear p-points is a projective invariant.
When the p-points lie on a chord of a projective conic, we get interesting results.

the cross-ratio theorem for a projective conic
Suppose A, B are distinct p-points on the projective conic C,
and that P,Q are distinct p-points on AB, but not on C. Then
P,Q both lie inside C or both lie outside C
if and only if (A,B,P,Q) is positive.

proof

This is related to

The polar-chord theorem
If a p-point P lies on the chord AB of a p-conic C, then the polar of P
with respect to C cuts the p-line AB at Q, where (A,B,P,Q) = -1.

Combining these, we have the

Corollary
If a p-point P lies on the chord AB of a p-conic C and the polar of P
cuts the p-line AB at Q, then exactly one of P,Q lies inside C .

Observe that this is trivial if P is inside C, for then the polar of P
does not cut C, so Q must lie outside C.

Suppose that P and Q lie inside C. Then the p-line PQ cuts C twice.
We can label these A and B in either order. By the theorem, we know
that (A,B,P,Q) is positive. From Remarks(1),(3), we see that
(B,A,P,Q) = 1/(A,B,P,Q), and the ratios are unequal as neither is 1.
It follows that one of the cross-ratios is less than 1. We make the

Definition
Suppose that P and Q are distinct p-points in the interior of a p-conic C.
Then D(P,Q) = (A,B,P,Q), where A and B are the p-points in which PQ
meets C, labelled so that (A,B,C,D) < 1. We set D(P,P) = 1.

We know that, for a p-conic C, the projective symmetry group S(C,P(2))
maps the interior of C to itself. We also know that any projective
transformation preserves cross-ratio. These remarks prove

the invariance theorem for D
For any projective conic C the function D is an invariant of S(C,P(2)).

In the geometry defined on the interior of C by the symmetry group
d = -log(D) is essentially a distance function since we have

  • d(P,P) = 0,
  • d(P,Q) > 0 if P ≠ Q,
  • d(P,Q) = d(Q,P).
Only the last needs comment. The proof uses Remark(1).
If PQ meets C in A and B with D(P,Q) = (A,B,P,Q) < 1, then
(A,B,Q,P) = 1/(A,B,P,Q). But this is greater than 1, so that
D(Q,P) = (B,A,Q,P) = 1/(A,B,Q,P) = D(P,Q).

We shall not pursue the triangle inequality. We already know
that the geometry is a model of hyperbolic geometry.

As a final example of the use of projective geometry to understand this
model of hyperbolic geometry, we will look at the projective analogue
of the interchange lemma, and some related ideas.

interior-exterior